10434011123131 has 4 divisors (see below), whose sum is σ = 10437917532064. Its totient is φ = 10430104714200.

The previous prime is 10434011123089. The next prime is 10434011123149. The reversal of 10434011123131 is 13132111043401.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10434011123131 is a prime.

It is a super-2 number, since 2×10434011123131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10434011123096 and 10434011123105.

It is not an unprimeable number, because it can be changed into a prime (10434011183131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1953200460 + ... + 1953205801.

It is an arithmetic number, because the mean of its divisors is an integer number (2609479383016).

Almost surely, 2^{10434011123131} is an apocalyptic number.

10434011123131 is a deficient number, since it is larger than the sum of its proper divisors (3906408933).

10434011123131 is an equidigital number, since it uses as much as digits as its factorization.

10434011123131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3906408932.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 10434011123131 its reverse (13132111043401), we get a palindrome (23566122166532).

The spelling of 10434011123131 in words is "ten trillion, four hundred thirty-four billion, eleven million, one hundred twenty-three thousand, one hundred thirty-one".