1043413441 has 4 divisors (see below), whose sum is σ = 1192472512. Its totient is φ = 894354372.

The previous prime is 1043413439. The next prime is 1043413451. The reversal of 1043413441 is 1443143401.

1043413441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1443143401 = 7 ⋅206163343.

It is a cyclic number.

It is not a de Polignac number, because 1043413441 - 2¹ = 1043413439 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1043413451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74529525 + ... + 74529538.

It is an arithmetic number, because the mean of its divisors is an integer number (298118128).

Almost surely, 2^1043413441 is an apocalyptic number.

It is an amenable number.

1043413441 is a deficient number, since it is larger than the sum of its proper divisors (149059071).

1043413441 is an equidigital number, since it uses as much as digits as its factorization.

1043413441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149059070.

The product of its (nonzero) digits is 2304, while the sum is 25.

The square root of 1043413441 is about 32301.9107948740. The cubic root of 1043413441 is about 1014.2666419960.

Adding to 1043413441 its reverse (1443143401), we get a palindrome (2486556842).

The spelling of 1043413441 in words is "one billion, forty-three million, four hundred thirteen thousand, four hundred forty-one".