1043440133 has 4 divisors (see below), whose sum is σ = 1043603040. Its totient is φ = 1043277228.

The previous prime is 1043440121. The next prime is 1043440147. The reversal of 1043440133 is 3310443401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3310443401 = 67 ⋅49409603.

It is a cyclic number.

It is not a de Polignac number, because 1043440133 - 2⁴ = 1043440117 is a prime.

It is a super-2 number, since 2×1043440133² = 2177534622310115378, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1043440099 and 1043440108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1043440163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71435 + ... + 84792.

It is an arithmetic number, because the mean of its divisors is an integer number (260900760).

Almost surely, 2^1043440133 is an apocalyptic number.

It is an amenable number.

1043440133 is a deficient number, since it is larger than the sum of its proper divisors (162907).

1043440133 is an equidigital number, since it uses as much as digits as its factorization.

1043440133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162906.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 1043440133 is about 32302.3239566444. The cubic root of 1043440133 is about 1014.2752907167.

Adding to 1043440133 its reverse (3310443401), we get a palindrome (4353883534).

The spelling of 1043440133 in words is "one billion, forty-three million, four hundred forty thousand, one hundred thirty-three".