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10472343333 = 33490781111
BaseRepresentation
bin10011100000011001…
…10100011100100101
31000000211120011100220
421300030310130211
5132421404441313
64451054354553
7520341310134
oct116014643445
930024504326
1010472343333
114494401601
1220431bba59
13cab80b07a
14714b9991b
154145b1823
hex270334725

10472343333 has 4 divisors (see below), whose sum is σ = 13963124448. Its totient is φ = 6981562220.

The previous prime is 10472343311. The next prime is 10472343361. The reversal of 10472343333 is 33334327401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10472343333 - 29 = 10472342821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10472343294 and 10472343303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10472343733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1745390553 + ... + 1745390558.

It is an arithmetic number, because the mean of its divisors is an integer number (3490781112).

Almost surely, 210472343333 is an apocalyptic number.

It is an amenable number.

10472343333 is a deficient number, since it is larger than the sum of its proper divisors (3490781115).

10472343333 is an equidigital number, since it uses as much as digits as its factorization.

10472343333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3490781114.

The product of its (nonzero) digits is 54432, while the sum is 33.

The spelling of 10472343333 in words is "ten billion, four hundred seventy-two million, three hundred forty-three thousand, three hundred thirty-three".

Divisors: 1 3 3490781111 10472343333