Base | Representation |
---|---|
bin | 110000111001101000… |
… | …0111110000011111011 |
3 | 101001001112120100001200 |
4 | 1201303100332003323 |
5 | 3210031314342301 |
6 | 120124201545243 |
7 | 10405215066351 |
oct | 1416320760373 |
9 | 331045510050 |
10 | 105013043451 |
11 | 40599141918 |
12 | 184287a5223 |
13 | 9b97287244 |
14 | 5122b597d1 |
15 | 2ae93bac86 |
hex | 187343e0fb |
105013043451 has 6 divisors (see below), whose sum is σ = 151685507220. Its totient is φ = 70008695628.
The previous prime is 105013043363. The next prime is 105013043479. The reversal of 105013043451 is 154340310501.
It is a happy number.
105013043451 is a `hidden beast` number, since 1 + 0 + 50 + 130 + 434 + 51 = 666.
It is a de Polignac number, because none of the positive numbers 2k-105013043451 is a prime.
It is a super-2 number, since 2×1050130434512 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (105013043851) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5834057961 + ... + 5834057978.
It is an arithmetic number, because the mean of its divisors is an integer number (25280917870).
Almost surely, 2105013043451 is an apocalyptic number.
105013043451 is a deficient number, since it is larger than the sum of its proper divisors (46672463769).
105013043451 is a wasteful number, since it uses less digits than its factorization.
105013043451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11668115945 (or 11668115942 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 105013043451 its reverse (154340310501), we get a palindrome (259353353952).
The spelling of 105013043451 in words is "one hundred five billion, thirteen million, forty-three thousand, four hundred fifty-one".
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