Base | Representation |
---|---|
bin | 11110100100001001100… |
… | …11100110100111011101 |
3 | 10201101202020211202220212 |
4 | 33102010303212213131 |
5 | 114201302213442003 |
6 | 2122242201422205 |
7 | 135605636622035 |
oct | 17220463464735 |
9 | 3641666752825 |
10 | 1050200140253 |
11 | 375429667310 |
12 | 14b651a9a965 |
13 | 78058641644 |
14 | 38b895948c5 |
15 | 1c4b8991dd8 |
hex | f484ce69dd |
1050200140253 has 16 divisors (see below), whose sum is σ = 1163026913280. Its totient is φ = 940271943600.
The previous prime is 1050200140237. The next prime is 1050200140259. The reversal of 1050200140253 is 3520410020501.
It is not a de Polignac number, because 1050200140253 - 24 = 1050200140237 is a prime.
It is a super-2 number, since 2×10502001402532 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1050200140259) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3265358 + ... + 3572528.
It is an arithmetic number, because the mean of its divisors is an integer number (72689182080).
Almost surely, 21050200140253 is an apocalyptic number.
It is an amenable number.
1050200140253 is a deficient number, since it is larger than the sum of its proper divisors (112826773027).
1050200140253 is a wasteful number, since it uses less digits than its factorization.
1050200140253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 311888.
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 1050200140253 its reverse (3520410020501), we get a palindrome (4570610160754).
The spelling of 1050200140253 in words is "one trillion, fifty billion, two hundred million, one hundred forty thousand, two hundred fifty-three".
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