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105025401241 = 848711237471
BaseRepresentation
bin110000111010000000…
…0000111000110011001
3101001002101211011202121
41201310000013012121
53210043000314431
6120125322501241
710405425116035
oct1416400070631
9331071734677
10105025401241
11405a5112472
1218430964821
139b999c3047
1451246551c5
152aea50c611
hex1874007199

105025401241 has 4 divisors (see below), whose sum is σ = 105026723584. Its totient is φ = 105024078900.

The previous prime is 105025401161. The next prime is 105025401251. The reversal of 105025401241 is 142104520501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 105025401241 - 217 = 105025270169 is a prime.

It is a super-2 number, since 2×1050254012412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (105025401251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 533865 + ... + 703606.

It is an arithmetic number, because the mean of its divisors is an integer number (26256680896).

Almost surely, 2105025401241 is an apocalyptic number.

It is an amenable number.

105025401241 is a deficient number, since it is larger than the sum of its proper divisors (1322343).

105025401241 is an equidigital number, since it uses as much as digits as its factorization.

105025401241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1322342.

The product of its (nonzero) digits is 1600, while the sum is 25.

Adding to 105025401241 its reverse (142104520501), we get a palindrome (247129921742).

The spelling of 105025401241 in words is "one hundred five billion, twenty-five million, four hundred one thousand, two hundred forty-one".

Divisors: 1 84871 1237471 105025401241