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1050505331433 = 3505969216929
BaseRepresentation
bin11110100100101101111…
…11110100001011101001
310201102112112010002111220
433102112333310023221
5114202413331101213
62122332343012253
7135616333662165
oct17222677641351
93642475102456
101050505331433
11375575966a28
1214b71813a089
13780a693923c
1438bb7d19ca5
151c4d5678e23
hexf496ff42e9

1050505331433 has 8 divisors (see below), whose sum is σ = 1400950663200. Its totient is φ = 700198443648.

The previous prime is 1050505331401. The next prime is 1050505331441. The reversal of 1050505331433 is 3341335050501.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1050505331433 - 25 = 1050505331401 is a prime.

It is a super-2 number, since 2×10505053314332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1050505331394 and 1050505331403.

It is not an unprimeable number, because it can be changed into a prime (1050505331333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34593288 + ... + 34623641.

It is an arithmetic number, because the mean of its divisors is an integer number (175118832900).

Almost surely, 21050505331433 is an apocalyptic number.

It is an amenable number.

1050505331433 is a deficient number, since it is larger than the sum of its proper divisors (350445331767).

1050505331433 is an equidigital number, since it uses as much as digits as its factorization.

1050505331433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69221991.

The product of its (nonzero) digits is 40500, while the sum is 33.

The spelling of 1050505331433 in words is "one trillion, fifty billion, five hundred five million, three hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 3 5059 15177 69216929 207650787 350168443811 1050505331433