Base | Representation |
---|---|
bin | 111110101110011… |
… | …010101000111101 |
3 | 2201100012011212001 |
4 | 332232122220331 |
5 | 4123400331013 |
6 | 252231342301 |
7 | 35035604524 |
oct | 7656325075 |
9 | 2640164761 |
10 | 1052355133 |
11 | 4a0032a95 |
12 | 254521991 |
13 | 13a03b55b |
14 | 9da994bb |
15 | 625c3ddd |
hex | 3eb9aa3d |
1052355133 has 4 divisors (see below), whose sum is σ = 1098109728. Its totient is φ = 1006600540.
The previous prime is 1052355067. The next prime is 1052355137. The reversal of 1052355133 is 3315532501.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1052355133 - 213 = 1052346941 is a prime.
It is a super-2 number, since 2×10523551332 = 2214902651902895378, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1052355137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22877263 + ... + 22877308.
It is an arithmetic number, because the mean of its divisors is an integer number (274527432).
Almost surely, 21052355133 is an apocalyptic number.
It is an amenable number.
1052355133 is a deficient number, since it is larger than the sum of its proper divisors (45754595).
1052355133 is an equidigital number, since it uses as much as digits as its factorization.
1052355133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45754594.
The product of its (nonzero) digits is 6750, while the sum is 28.
The square root of 1052355133 is about 32440.0236282281. The cubic root of 1052355133 is about 1017.1557095497.
Adding to 1052355133 its reverse (3315532501), we get a palindrome (4367887634).
It can be divided in two parts, 10523 and 55133, that added together give a palindrome (65656).
The spelling of 1052355133 in words is "one billion, fifty-two million, three hundred fifty-five thousand, one hundred thirty-three".
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