Base | Representation |
---|---|
bin | 11110101010001000011… |
… | …01010101011110100101 |
3 | 10201201001001021022200120 |
4 | 33111010031111132211 |
5 | 114224341300142203 |
6 | 2123532552432153 |
7 | 136051341413061 |
oct | 17250415253645 |
9 | 3651031238616 |
10 | 1053411334053 |
11 | 376827265791 |
12 | 1501a93a8659 |
13 | 7844a9cc210 |
14 | 38db1c54aa1 |
15 | 1c605851b53 |
hex | f5443557a5 |
1053411334053 has 16 divisors (see below), whose sum is σ = 1512772966656. Its totient is φ = 648174985920.
The previous prime is 1053411334051. The next prime is 1053411334099. The reversal of 1053411334053 is 3504331143501.
It is not a de Polignac number, because 1053411334053 - 21 = 1053411334051 is a prime.
It is a super-2 number, since 2×10534113340532 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1053411334051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1299453 + ... + 1948178.
It is an arithmetic number, because the mean of its divisors is an integer number (94548310416).
Almost surely, 21053411334053 is an apocalyptic number.
1053411334053 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1053411334053 is a deficient number, since it is larger than the sum of its proper divisors (459361632603).
1053411334053 is a wasteful number, since it uses less digits than its factorization.
1053411334053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3255964.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 1053411334053 its reverse (3504331143501), we get a palindrome (4557742477554).
The spelling of 1053411334053 in words is "one trillion, fifty-three billion, four hundred eleven million, three hundred thirty-four thousand, fifty-three".
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