Base | Representation |
---|---|
bin | 11110101010001000101… |
… | …11100000101001001001 |
3 | 10201201001020021211100201 |
4 | 33111010113200221021 |
5 | 114224342441014400 |
6 | 2123533125532201 |
7 | 136051403162065 |
oct | 17250427405111 |
9 | 3651036254321 |
10 | 1053414001225 |
11 | 376828817663 |
12 | 1501aa274061 |
13 | 7844b424221 |
14 | 38db234aaa5 |
15 | 1c605bcc06a |
hex | f5445e0a49 |
1053414001225 has 6 divisors (see below), whose sum is σ = 1306233361550. Its totient is φ = 842731200960.
The previous prime is 1053414001187. The next prime is 1053414001253. The reversal of 1053414001225 is 5221004143501.
It can be written as a sum of positive squares in 3 ways, for example, as 265566039561 + 787847961664 = 515331^2 + 887608^2 .
It is not a de Polignac number, because 1053414001225 - 217 = 1053413870153 is a prime.
It is a super-2 number, since 2×10534140012252 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1053414001193 and 1053414001202.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 21068280000 + ... + 21068280049.
Almost surely, 21053414001225 is an apocalyptic number.
It is an amenable number.
1053414001225 is a deficient number, since it is larger than the sum of its proper divisors (252819360325).
1053414001225 is an equidigital number, since it uses as much as digits as its factorization.
1053414001225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42136560059 (or 42136560054 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 1053414001225 its reverse (5221004143501), we get a palindrome (6274418144726).
The spelling of 1053414001225 in words is "one trillion, fifty-three billion, four hundred fourteen million, one thousand, two hundred twenty-five".
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