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105400325145 = 357026688343
BaseRepresentation
bin110001000101001011…
…0010101010000011001
3101002001112022021200010
41202022112111100121
53211324440401040
6120230434432133
710420626660453
oct1421226252031
9332045267603
10105400325145
1140777810335
1218516432649
139c295948cb
14515c36d2d3
152b1d3bae80
hex188a595419

105400325145 has 8 divisors (see below), whose sum is σ = 168640520256. Its totient is φ = 56213506736.

The previous prime is 105400325137. The next prime is 105400325231. The reversal of 105400325145 is 541523004501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 105400325145 - 23 = 105400325137 is a prime.

It is a super-2 number, since 2×1054003251452 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3513344157 + ... + 3513344186.

It is an arithmetic number, because the mean of its divisors is an integer number (21080065032).

Almost surely, 2105400325145 is an apocalyptic number.

105400325145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

105400325145 is a deficient number, since it is larger than the sum of its proper divisors (63240195111).

105400325145 is an equidigital number, since it uses as much as digits as its factorization.

105400325145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7026688351.

The product of its (nonzero) digits is 12000, while the sum is 30.

Adding to 105400325145 its reverse (541523004501), we get a palindrome (646923329646).

The spelling of 105400325145 in words is "one hundred five billion, four hundred million, three hundred twenty-five thousand, one hundred forty-five".

Divisors: 1 3 5 15 7026688343 21080065029 35133441715 105400325145