Base | Representation |
---|---|
bin | 1001100101101000000110… |
… | …0011000111111111111111 |
3 | 1101022210210201112101010020 |
4 | 2121122001203013333333 |
5 | 2340210030420304210 |
6 | 34230534423343223 |
7 | 2135431106550045 |
oct | 231320143077777 |
9 | 41283721471106 |
10 | 10542023213055 |
11 | 33a4935301464 |
12 | 12231462b1b13 |
13 | 5b615456c929 |
14 | 2863454dc395 |
15 | 13434eea8770 |
hex | 996818c7fff |
10542023213055 has 16 divisors (see below), whose sum is σ = 16867708116480. Its totient is φ = 5622255388448.
The previous prime is 10542023213023. The next prime is 10542023213081. The reversal of 10542023213055 is 55031232024501.
It is a cyclic number.
It is not a de Polignac number, because 10542023213055 - 25 = 10542023213023 is a prime.
It is a super-3 number, since 3×105420232130553 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9255867 + ... + 10332236.
It is an arithmetic number, because the mean of its divisors is an integer number (1054231757280).
Almost surely, 210542023213055 is an apocalyptic number.
10542023213055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10542023213055 is a deficient number, since it is larger than the sum of its proper divisors (6325684903425).
10542023213055 is a wasteful number, since it uses less digits than its factorization.
10542023213055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19623990.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 10542023213055 its reverse (55031232024501), we get a palindrome (65573255237556).
The spelling of 10542023213055 in words is "ten trillion, five hundred forty-two billion, twenty-three million, two hundred thirteen thousand, fifty-five".
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