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1054331405345 = 5316802138099
BaseRepresentation
bin11110101011110110000…
…11001000010000100001
310201210102011112210020002
433111323003020100201
5114233232314432340
62124204141025345
7136113213035501
oct17257303102041
93653364483202
101054331405345
11377159656989
12150405555255
13785665025ba
143905c117a01
151c65b4e5715
hexf57b0c8421

1054331405345 has 8 divisors (see below), whose sum is σ = 1306010515200. Its totient is φ = 816256571760.

The previous prime is 1054331405311. The next prime is 1054331405359. The reversal of 1054331405345 is 5435041334501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1054331405345 - 220 = 1054330356769 is a prime.

It is a super-2 number, since 2×10543314053452 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1054331405299 and 1054331405308.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3401068895 + ... + 3401069204.

It is an arithmetic number, because the mean of its divisors is an integer number (163251314400).

Almost surely, 21054331405345 is an apocalyptic number.

It is an amenable number.

1054331405345 is a deficient number, since it is larger than the sum of its proper divisors (251679109855).

1054331405345 is an equidigital number, since it uses as much as digits as its factorization.

1054331405345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6802138135.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 1054331405345 its reverse (5435041334501), we get a palindrome (6489372739846).

The spelling of 1054331405345 in words is "one trillion, fifty-four billion, three hundred thirty-one million, four hundred five thousand, three hundred forty-five".

Divisors: 1 5 31 155 6802138099 34010690495 210866281069 1054331405345