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10543354225007 = 75391139848977
BaseRepresentation
bin1001100101101101000011…
…1000100010000101101111
31101022221020111001210021012
42121123100320202011233
52340220242140200012
634231314451455435
72135506101142262
oct231332070420557
941287214053235
1010543354225007
1133a545866043a
121223457bb757b
135b6307245376
142864301b2cd9
151343cbc72622
hex996d0e2216f

10543354225007 has 4 divisors (see below), whose sum is σ = 10543494149376. Its totient is φ = 10543214300640.

The previous prime is 10543354225003. The next prime is 10543354225013. The reversal of 10543354225007 is 70052245334501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10543354225007 - 22 = 10543354225003 is a prime.

It is a super-2 number, since 2×105433542250072 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10543354225003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69849098 + ... + 69999879.

It is an arithmetic number, because the mean of its divisors is an integer number (2635873537344).

Almost surely, 210543354225007 is an apocalyptic number.

10543354225007 is a deficient number, since it is larger than the sum of its proper divisors (139924369).

10543354225007 is an equidigital number, since it uses as much as digits as its factorization.

10543354225007 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139924368.

The product of its (nonzero) digits is 504000, while the sum is 41.

Adding to 10543354225007 its reverse (70052245334501), we get a palindrome (80595599559508).

The spelling of 10543354225007 in words is "ten trillion, five hundred forty-three billion, three hundred fifty-four million, two hundred twenty-five thousand, seven".

Divisors: 1 75391 139848977 10543354225007