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105511010001 = 335170336667
BaseRepresentation
bin110001001000011110…
…0100011111011010001
3101002100020120122202020
41202100330203323101
53212041304310001
6120245431042053
710423442534025
oct1422074437321
9332306518666
10105511010001
114082423a521
1218547510329
139c464a98c7
14516cd42385
152b27e81736
hex1890f23ed1

105511010001 has 4 divisors (see below), whose sum is σ = 140681346672. Its totient is φ = 70340673332.

The previous prime is 105511009939. The next prime is 105511010023. The reversal of 105511010001 is 100010115501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 105511010001 - 27 = 105511009873 is a prime.

It is a super-2 number, since 2×1055110100012 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (105511010081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17585168331 + ... + 17585168336.

It is an arithmetic number, because the mean of its divisors is an integer number (35170336668).

Almost surely, 2105511010001 is an apocalyptic number.

It is an amenable number.

105511010001 is a deficient number, since it is larger than the sum of its proper divisors (35170336671).

105511010001 is an equidigital number, since it uses as much as digits as its factorization.

105511010001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35170336670.

The product of its (nonzero) digits is 25, while the sum is 15.

Adding to 105511010001 its reverse (100010115501), we get a palindrome (205521125502).

The spelling of 105511010001 in words is "one hundred five billion, five hundred eleven million, ten thousand, one".

Divisors: 1 3 35170336667 105511010001