Base | Representation |
---|---|
bin | 111110111000111… |
… | …011100010000111 |
3 | 2201112101012121102 |
4 | 332320323202013 |
5 | 4130102030203 |
6 | 252410410315 |
7 | 35101204151 |
oct | 7670734207 |
9 | 2645335542 |
10 | 1055111303 |
11 | 4a1645814 |
12 | 25543099b |
13 | 13a794c1c |
14 | a01b5ad1 |
15 | 6296a888 |
hex | 3ee3b887 |
1055111303 has 4 divisors (see below), whose sum is σ = 1055180568. Its totient is φ = 1055042040.
The previous prime is 1055111279. The next prime is 1055111329. The reversal of 1055111303 is 3031115501.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 1055111303 - 216 = 1055045767 is a prime.
It is a super-2 number, since 2×10551113032 = 2226519723436715618, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1055111353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 701 + ... + 45942.
It is an arithmetic number, because the mean of its divisors is an integer number (263795142).
Almost surely, 21055111303 is an apocalyptic number.
1055111303 is a deficient number, since it is larger than the sum of its proper divisors (69265).
1055111303 is an equidigital number, since it uses as much as digits as its factorization.
1055111303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69264.
The product of its (nonzero) digits is 225, while the sum is 20.
The square root of 1055111303 is about 32482.4768606090. The cubic root of 1055111303 is about 1018.0429291006.
Adding to 1055111303 its reverse (3031115501), we get a palindrome (4086226804).
The spelling of 1055111303 in words is "one billion, fifty-five million, one hundred eleven thousand, three hundred three".
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