Base | Representation |
---|---|
bin | 110001001000100100… |
… | …0011010000000111011 |
3 | 101002100110102102012001 |
4 | 1202101020122000323 |
5 | 3212043103141011 |
6 | 120250021401431 |
7 | 10423511115625 |
oct | 1422110320073 |
9 | 332313372161 |
10 | 105514115131 |
11 | 40825a70447 |
12 | 18548569277 |
13 | 9c47026069 |
14 | 516d50dc15 |
15 | 2b283967c1 |
hex | 189121a03b |
105514115131 has 4 divisors (see below), whose sum is σ = 107759096352. Its totient is φ = 103269133912.
The previous prime is 105514115099. The next prime is 105514115137. The reversal of 105514115131 is 131511415501.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 105514115131 - 25 = 105514115099 is a prime.
It is a super-2 number, since 2×1055141151312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 105514115131.
It is not an unprimeable number, because it can be changed into a prime (105514115137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1122490540 + ... + 1122490633.
It is an arithmetic number, because the mean of its divisors is an integer number (26939774088).
Almost surely, 2105514115131 is an apocalyptic number.
105514115131 is a deficient number, since it is larger than the sum of its proper divisors (2244981221).
105514115131 is an equidigital number, since it uses as much as digits as its factorization.
105514115131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2244981220.
The product of its (nonzero) digits is 1500, while the sum is 28.
The spelling of 105514115131 in words is "one hundred five billion, five hundred fourteen million, one hundred fifteen thousand, one hundred thirty-one".
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