Base | Representation |
---|---|
bin | 10111111111100001010010… |
… | …001000101111101010010111 |
3 | 111211121121220121100121010112 |
4 | 113333201102020233222113 |
5 | 102312320213421132330 |
6 | 1012231140335513235 |
7 | 31140402205511345 |
oct | 2777412210575227 |
9 | 454547817317115 |
10 | 105520134552215 |
11 | 30692924061229 |
12 | ba0261368881b |
13 | 46b56768833a6 |
14 | 1c0b2b78ca995 |
15 | c2ec4a5bc795 |
hex | 5ff85222fa97 |
105520134552215 has 16 divisors (see below), whose sum is σ = 126929365718400. Its totient is φ = 84212673365760.
The previous prime is 105520134552187. The next prime is 105520134552221. The reversal of 105520134552215 is 512255431025501.
It is not a de Polignac number, because 105520134552215 - 214 = 105520134535831 is a prime.
It is a super-3 number, since 3×1055201345522153 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21830147 + ... + 26222043.
It is an arithmetic number, because the mean of its divisors is an integer number (7933085357400).
Almost surely, 2105520134552215 is an apocalyptic number.
105520134552215 is a deficient number, since it is larger than the sum of its proper divisors (21409231166185).
105520134552215 is a wasteful number, since it uses less digits than its factorization.
105520134552215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4403482.
The product of its (nonzero) digits is 300000, while the sum is 41.
Adding to 105520134552215 its reverse (512255431025501), we get a palindrome (617775565577716).
The spelling of 105520134552215 in words is "one hundred five trillion, five hundred twenty billion, one hundred thirty-four million, five hundred fifty-two thousand, two hundred fifteen".
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