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10553120035 = 51092177647
BaseRepresentation
bin10011101010000001…
…11101010100100011
31000020110120001011121
421311000331110203
5133103044320120
64503101553111
7522342016543
oct116500752443
930213501147
1010553120035
114525a63307
122066275797
13cc2480b33
147217c5323
1541b71a5aa
hex27503d523

10553120035 has 12 divisors (see below), whose sum is σ = 12781063008. Its totient is φ = 8364994848.

The previous prime is 10553120033. The next prime is 10553120063. The reversal of 10553120035 is 53002135501.

It is not a de Polignac number, because 10553120035 - 21 = 10553120033 is a prime.

It is a super-2 number, since 2×105531200352 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10553119991 and 10553120009.

It is not an unprimeable number, because it can be changed into a prime (10553120033) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 29419 + ... + 148228.

It is an arithmetic number, because the mean of its divisors is an integer number (1065088584).

Almost surely, 210553120035 is an apocalyptic number.

10553120035 is a deficient number, since it is larger than the sum of its proper divisors (2227942973).

10553120035 is an equidigital number, since it uses as much as digits as its factorization.

10553120035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177870 (or 177761 counting only the distinct ones).

The product of its (nonzero) digits is 2250, while the sum is 25.

Adding to 10553120035 its reverse (53002135501), we get a palindrome (63555255536).

The spelling of 10553120035 in words is "ten billion, five hundred fifty-three million, one hundred twenty thousand, thirty-five".

Divisors: 1 5 109 545 11881 59405 177647 888235 19363523 96817615 2110624007 10553120035