Base | Representation |
---|---|
bin | 110001001100000111… |
… | …0110001000111001001 |
3 | 101002122202112201121210 |
4 | 1202120032301013021 |
5 | 3212314101114423 |
6 | 120305514323333 |
7 | 10426455403335 |
oct | 1423016610711 |
9 | 332582481553 |
10 | 105633223113 |
11 | 40887222aa0 |
12 | 18580429549 |
13 | 9c658c9c62 |
14 | 51812767c5 |
15 | 2b33a72b93 |
hex | 18983b11c9 |
105633223113 has 16 divisors (see below), whose sum is σ = 160328687616. Its totient is φ = 61236650640.
The previous prime is 105633223109. The next prime is 105633223117. The reversal of 105633223113 is 311322336501.
It is an interprime number because it is at equal distance from previous prime (105633223109) and next prime (105633223117).
It is not a de Polignac number, because 105633223113 - 22 = 105633223109 is a prime.
It is a super-2 number, since 2×1056332231132 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (105633223117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69586345 + ... + 69587862.
It is an arithmetic number, because the mean of its divisors is an integer number (10020542976).
Almost surely, 2105633223113 is an apocalyptic number.
It is an amenable number.
105633223113 is a deficient number, since it is larger than the sum of its proper divisors (54695464503).
105633223113 is a wasteful number, since it uses less digits than its factorization.
105633223113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139174244.
The product of its (nonzero) digits is 9720, while the sum is 30.
Adding to 105633223113 its reverse (311322336501), we get a palindrome (416955559614).
The spelling of 105633223113 in words is "one hundred five billion, six hundred thirty-three million, two hundred twenty-three thousand, one hundred thirteen".
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