Search a number
-
+
106340551113 = 337958022983
BaseRepresentation
bin110001100001001100…
…1000000100111001001
3101011111001111201020010
41203002121000213021
53220241140113423
6120504023022133
710453134525156
oct1430231004711
9334431451203
10106340551113
114110a517a95
121873929a949
13a049303934
14520b19b22d
152b75be1693
hex18c26409c9

106340551113 has 8 divisors (see below), whose sum is σ = 145619493568. Its totient is φ = 68977654704.

The previous prime is 106340551073. The next prime is 106340551123. The reversal of 106340551113 is 311155043601.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 106340551113 - 217 = 106340420041 is a prime.

It is a super-2 number, since 2×1063405511132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (106340551123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 479011381 + ... + 479011602.

It is an arithmetic number, because the mean of its divisors is an integer number (18202436696).

Almost surely, 2106340551113 is an apocalyptic number.

It is an amenable number.

106340551113 is a deficient number, since it is larger than the sum of its proper divisors (39278942455).

106340551113 is an equidigital number, since it uses as much as digits as its factorization.

106340551113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 958023023.

The product of its (nonzero) digits is 5400, while the sum is 30.

Adding to 106340551113 its reverse (311155043601), we get a palindrome (417495594714).

The spelling of 106340551113 in words is "one hundred six billion, three hundred forty million, five hundred fifty-one thousand, one hundred thirteen".

Divisors: 1 3 37 111 958022983 2874068949 35446850371 106340551113