10959433 has 4 divisors (see below), whose sum is σ = 11098240. Its totient is φ = 10820628.

The previous prime is 10959401. The next prime is 10959439. The reversal of 10959433 is 33495901.

10959433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33495901 = 733 ⋅45697.

It is a cyclic number.

It is not a de Polignac number, because 10959433 - 2⁵ = 10959401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10959439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69285 + ... + 69442.

It is an arithmetic number, because the mean of its divisors is an integer number (2774560).

Almost surely, 2^10959433 is an apocalyptic number.

It is an amenable number.

10959433 is a deficient number, since it is larger than the sum of its proper divisors (138807).

10959433 is an equidigital number, since it uses as much as digits as its factorization.

10959433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 138806.

The product of its (nonzero) digits is 14580, while the sum is 34.

The square root of 10959433 is about 3310.5034360351. The cubic root of 10959433 is about 222.1242777354.

The spelling of 10959433 in words is "ten million, nine hundred fifty-nine thousand, four hundred thirty-three".