109753642540831 has 4 divisors (see below), whose sum is σ = 115530150043000. Its totient is φ = 103977135038664.

The previous prime is 109753642540783. The next prime is 109753642540847. The reversal of 109753642540831 is 138045246357901.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 109753642540831 - 2¹¹ = 109753642538783 is a prime.

It is a super-2 number, since 2×109753642540831² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (109753642540231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2888253751056 + ... + 2888253751093.

It is an arithmetic number, because the mean of its divisors is an integer number (28882537510750).

It is a 1-persistent number, because it is pandigital, but 2⋅109753642540831 = 219507285081662 is not.

Almost surely, 2^{109753642540831} is an apocalyptic number.

109753642540831 is a deficient number, since it is larger than the sum of its proper divisors (5776507502169).

109753642540831 is an equidigital number, since it uses as much as digits as its factorization.

109753642540831 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5776507502168.

The product of its (nonzero) digits is 21772800, while the sum is 58.

The spelling of 109753642540831 in words is "one hundred nine trillion, seven hundred fifty-three billion, six hundred forty-two million, five hundred forty thousand, eight hundred thirty-one".