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110000110220012 = 2227500027555003
BaseRepresentation
bin11001000000101101100101…
…011111101011001011101100
3112102110220111210221112112202
4121000231211133223023230
5103404220211204020022
61025541204130121032
732112150163415645
oct3100554537531354
9472426453845482
10110000110220012
113205a86a582111
1210406912420178
13494bc730829bc
141d240688326cc
15cab54e235592
hex640b657eb2ec

110000110220012 has 6 divisors (see below), whose sum is σ = 192500192885028. Its totient is φ = 55000055110004.

The previous prime is 110000110219933. The next prime is 110000110220047. The reversal of 110000110220012 is 210022011000011.

It is a super-3 number, since 3×1100001102200123 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110000110219975 and 110000110220002.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13750013777498 + ... + 13750013777505.

It is an arithmetic number, because the mean of its divisors is an integer number (32083365480838).

Almost surely, 2110000110220012 is an apocalyptic number.

It is an amenable number.

110000110220012 is a deficient number, since it is larger than the sum of its proper divisors (82500082665016).

110000110220012 is a wasteful number, since it uses less digits than its factorization.

110000110220012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27500027555007 (or 27500027555005 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 110000110220012 its reverse (210022011000011), we get a palindrome (320022121220023).

The spelling of 110000110220012 in words is "one hundred ten trillion, one hundred ten million, two hundred twenty thousand, twelve".

Divisors: 1 2 4 27500027555003 55000055110006 110000110220012