Base | Representation |
---|---|
bin | 10000000000011101001… |
… | …011101001010111000010 |
3 | 10220011021222100202022012 |
4 | 100000131023221113002 |
5 | 121010300303020114 |
6 | 2201200015412522 |
7 | 142321025045333 |
oct | 20003513512702 |
9 | 3804258322265 |
10 | 1100001220034 |
11 | 394565014692 |
12 | 159230224142 |
13 | 7c9641146a2 |
14 | 3b35170428a |
15 | 1d930b4263e |
hex | 1001d2e95c2 |
1100001220034 has 4 divisors (see below), whose sum is σ = 1650001830054. Its totient is φ = 550000610016.
The previous prime is 1100001220027. The next prime is 1100001220061. The reversal of 1100001220034 is 4300221000011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1065220089025 + 34781131009 = 1032095^2 + 186497^2 .
It is a super-2 number, since 2×11000012200342 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275000305007 + ... + 275000305010.
Almost surely, 21100001220034 is an apocalyptic number.
1100001220034 is a deficient number, since it is larger than the sum of its proper divisors (550000610020).
1100001220034 is an equidigital number, since it uses as much as digits as its factorization.
1100001220034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 550000610019.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 1100001220034 its reverse (4300221000011), we get a palindrome (5400222220045).
The spelling of 1100001220034 in words is "one trillion, one hundred billion, one million, two hundred twenty thousand, thirty-four".
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