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110001002113 = 1931186758917
BaseRepresentation
bin110011001110010010…
…0100001011010000001
3101111221011021220000101
41212130210201122001
53300240224031423
6122311143122401
710642633043032
oct1463444413201
9344834256011
10110001002113
1142718775002
121939b143401
13a4b078b082
1454773a4a89
152cdc2447ad
hex199c921681

110001002113 has 8 divisors (see below), whose sum is σ = 119525707520. Its totient is φ = 100849814640.

The previous prime is 110001002057. The next prime is 110001002131. The reversal of 110001002113 is 311200100011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110001002113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 110001002113.

It is not an unprimeable number, because it can be changed into a prime (110001002413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 93378870 + ... + 93380047.

It is an arithmetic number, because the mean of its divisors is an integer number (14940713440).

Almost surely, 2110001002113 is an apocalyptic number.

It is an amenable number.

110001002113 is a deficient number, since it is larger than the sum of its proper divisors (9524705407).

110001002113 is a wasteful number, since it uses less digits than its factorization.

110001002113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 186758967.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 110001002113 its reverse (311200100011), we get a palindrome (421201102124).

The spelling of 110001002113 in words is "one hundred ten billion, one million, two thousand, one hundred thirteen".

Divisors: 1 19 31 589 186758917 3548419423 5789526427 110001002113