Base | Representation |
---|---|
bin | 11001000000101110011101… |
… | …110100001001011001100001 |
3 | 112102110222221122220221222010 |
4 | 121000232131310021121201 |
5 | 103404224130102021003 |
6 | 1025541442002303133 |
7 | 32112212456022312 |
oct | 3100563564113141 |
9 | 472428848827863 |
10 | 110001055110753 |
11 | 32060204985554 |
12 | 10406b36957aa9 |
13 | 494c093a66051 |
14 | 1d24118116609 |
15 | cab5a717d003 |
hex | 640b9dd09661 |
110001055110753 has 16 divisors (see below), whose sum is σ = 148049896692096. Its totient is φ = 72646122583680.
The previous prime is 110001055110719. The next prime is 110001055110763. The reversal of 110001055110753 is 357011550100011.
It is not a de Polignac number, because 110001055110753 - 29 = 110001055110241 is a prime.
It is a super-3 number, since 3×1100010551107533 (a number of 43 digits) contains 333 as substring.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 110001055110753.
It is not an unprimeable number, because it can be changed into a prime (110001055110703) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 374534068 + ... + 374827653.
It is an arithmetic number, because the mean of its divisors is an integer number (9253118543256).
Almost surely, 2110001055110753 is an apocalyptic number.
It is an amenable number.
110001055110753 is a deficient number, since it is larger than the sum of its proper divisors (38048841581343).
110001055110753 is a wasteful number, since it uses less digits than its factorization.
110001055110753 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 749362184.
The product of its (nonzero) digits is 2625, while the sum is 30.
The spelling of 110001055110753 in words is "one hundred ten trillion, one billion, fifty-five million, one hundred ten thousand, seven hundred fifty-three".
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