110001301032023 has 4 divisors (see below), whose sum is σ = 110079371509680. Its totient is φ = 109923230554368.

The previous prime is 110001301032017. The next prime is 110001301032043. The reversal of 110001301032023 is 320230103100011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110001301032023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110001301031992 and 110001301032010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110001301032043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39035236715 + ... + 39035239532.

It is an arithmetic number, because the mean of its divisors is an integer number (27519842877420).

Almost surely, 2^{110001301032023} is an apocalyptic number.

110001301032023 is a deficient number, since it is larger than the sum of its proper divisors (78070477657).

110001301032023 is an equidigital number, since it uses as much as digits as its factorization.

110001301032023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78070477656.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 110001301032023 its reverse (320230103100011), we get a palindrome (430231404132034).

The spelling of 110001301032023 in words is "one hundred ten trillion, one billion, three hundred one million, thirty-two thousand, twenty-three".