11000133040141 has 4 divisors (see below), whose sum is σ = 12571580617312. Its totient is φ = 9428685462972.

The previous prime is 11000133040079. The next prime is 11000133040153. The reversal of 11000133040141 is 14104033100011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11000133040141 - 2¹⁷ = 11000132909069 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000133050141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 785723788575 + ... + 785723788588.

It is an arithmetic number, because the mean of its divisors is an integer number (3142895154328).

Almost surely, 2^{11000133040141} is an apocalyptic number.

It is an amenable number.

11000133040141 is a deficient number, since it is larger than the sum of its proper divisors (1571447577171).

11000133040141 is an equidigital number, since it uses as much as digits as its factorization.

11000133040141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1571447577170.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11000133040141 its reverse (14104033100011), we get a palindrome (25104166140152).

The spelling of 11000133040141 in words is "eleven trillion, one hundred thirty-three million, forty thousand, one hundred forty-one".