1100013312131 has 4 divisors (see below), whose sum is σ = 1100023531992. Its totient is φ = 1100003092272.

The previous prime is 1100013312091. The next prime is 1100013312133. The reversal of 1100013312131 is 1312133100011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100013312131 - 2¹⁸ = 1100013049987 is a prime.

It is a super-2 number, since 2×1100013312131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100013312133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4946741 + ... + 5164326.

It is an arithmetic number, because the mean of its divisors is an integer number (275005882998).

Almost surely, 2^{1100013312131} is an apocalyptic number.

1100013312131 is a deficient number, since it is larger than the sum of its proper divisors (10219861).

1100013312131 is a wasteful number, since it uses less digits than its factorization.

1100013312131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10219860.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1100013312131 its reverse (1312133100011), we get a palindrome (2412146412142).

The spelling of 1100013312131 in words is "one trillion, one hundred billion, thirteen million, three hundred twelve thousand, one hundred thirty-one".