1100013312091 has 2 divisors, whose sum is σ = 1100013312092. Its totient is φ = 1100013312090.

The previous prime is 1100013312019. The next prime is 1100013312133. The reversal of 1100013312091 is 1902133100011.

Together with previous prime (1100013312019) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1100013312091 - 2¹⁹ = 1100012787803 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100013312791) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006656045 + 550006656046.

It is an arithmetic number, because the mean of its divisors is an integer number (550006656046).

Almost surely, 2^{1100013312091} is an apocalyptic number.

1100013312091 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100013312091 is an equidigital number, since it uses as much as digits as its factorization.

1100013312091 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 22.

The spelling of 1100013312091 in words is "one trillion, one hundred billion, thirteen million, three hundred twelve thousand, ninety-one".