Base | Representation |
---|---|
bin | 10000000000011101111… |
… | …101101100100000100101 |
3 | 10220011022220001022200210 |
4 | 100000131331230200211 |
5 | 121010312132341013 |
6 | 2201201204530033 |
7 | 142321244421342 |
oct | 20003575544045 |
9 | 3804286038623 |
10 | 1100014340133 |
11 | 394571465a45 |
12 | 1592346b0919 |
13 | 7c966a59467 |
14 | 3b35335b7c9 |
15 | 1d931d84cc3 |
hex | 1001df6c825 |
1100014340133 has 8 divisors (see below), whose sum is σ = 1467614663200. Its totient is φ = 732878455248.
The previous prime is 1100014340021. The next prime is 1100014340171. The reversal of 1100014340133 is 3310434100011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1100014340133 - 28 = 1100014339877 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100014340233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 116104018 + ... + 116113491.
It is an arithmetic number, because the mean of its divisors is an integer number (183451832900).
Almost surely, 21100014340133 is an apocalyptic number.
It is an amenable number.
1100014340133 is a deficient number, since it is larger than the sum of its proper divisors (367600323067).
1100014340133 is a wasteful number, since it uses less digits than its factorization.
1100014340133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 232219091.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1100014340133 its reverse (3310434100011), we get a palindrome (4410448440144).
The spelling of 1100014340133 in words is "one trillion, one hundred billion, fourteen million, three hundred forty thousand, one hundred thirty-three".
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