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110002112002003 = 138461700923231
BaseRepresentation
bin11001000000101111011100…
…110011110111011111010011
3112102111002200022122121012111
4121000233130303313133103
5103404233311133031003
61025542134515210151
732112250611322024
oct3100573463673723
9472432608577174
10110002112002003
11320606a75265a1
12104071908a6957
13494c201a021a0
141d241b8632c4b
15cab619d4ae6d
hex640bdccf77d3

110002112002003 has 4 divisors (see below), whose sum is σ = 118463812925248. Its totient is φ = 101540411078760.

The previous prime is 110002112001953. The next prime is 110002112002037. The reversal of 110002112002003 is 300200211200011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 110002112002003 - 213 = 110002111993811 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 8461700923231 = 110002112002003 / (1 + 1 + 0 + 0 + 0 + 2 + 1 + 1 + 2 + 0 + 0 + 2 + 0 + 0 + 3).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110002112002043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4230850461603 + ... + 4230850461628.

It is an arithmetic number, because the mean of its divisors is an integer number (29615953231312).

Almost surely, 2110002112002003 is an apocalyptic number.

110002112002003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

110002112002003 is a deficient number, since it is larger than the sum of its proper divisors (8461700923245).

110002112002003 is an equidigital number, since it uses as much as digits as its factorization.

110002112002003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8461700923244.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 110002112002003 its reverse (300200211200011), we get a palindrome (410202323202014).

The spelling of 110002112002003 in words is "one hundred ten trillion, two billion, one hundred twelve million, two thousand, three".

Divisors: 1 13 8461700923231 110002112002003