110002131113 has 4 divisors (see below), whose sum is σ = 125716721280. Its totient is φ = 94287540948.

The previous prime is 110002131101. The next prime is 110002131121. The reversal of 110002131113 is 311131200011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110002131113 - 2⁶ = 110002131049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (110002131143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7857295073 + ... + 7857295086.

It is an arithmetic number, because the mean of its divisors is an integer number (31429180320).

Almost surely, 2^110002131113 is an apocalyptic number.

It is an amenable number.

110002131113 is a deficient number, since it is larger than the sum of its proper divisors (15714590167).

110002131113 is an equidigital number, since it uses as much as digits as its factorization.

110002131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15714590166.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 110002131113 its reverse (311131200011), we get a palindrome (421133331124).

The spelling of 110002131113 in words is "one hundred ten billion, two million, one hundred thirty-one thousand, one hundred thirteen".