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1100022000003 = 32196432877193
BaseRepresentation
bin10000000000011110011…
…010111010100110000011
310220011100102110111001200
4100000132122322212003
5121010321113000003
62201202041032243
7142321366503333
oct20003632724603
93804312414050
101100022000003
11394575817a13
12159237185683
137c96850bb24
143b3543930c3
151d9328996a3
hex1001e6ba983

1100022000003 has 12 divisors (see below), whose sum is σ = 1672548070440. Its totient is φ = 694750736736.

The previous prime is 1100021999983. The next prime is 1100022000013. The reversal of 1100022000003 is 3000002200011.

It is a happy number.

It is not a de Polignac number, because 1100022000003 - 221 = 1100019902851 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is not an unprimeable number, because it can be changed into a prime (1100022000013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3216438426 + ... + 3216438767.

It is an arithmetic number, because the mean of its divisors is an integer number (139379005870).

Almost surely, 21100022000003 is an apocalyptic number.

1100022000003 is a deficient number, since it is larger than the sum of its proper divisors (572526070437).

1100022000003 is a wasteful number, since it uses less digits than its factorization.

1100022000003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6432877218 (or 6432877215 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 9.

Adding to 1100022000003 its reverse (3000002200011), we get a palindrome (4100024200014).

The spelling of 1100022000003 in words is "one trillion, one hundred billion, twenty-two million, three", and thus it is an aban number.

Divisors: 1 3 9 19 57 171 6432877193 19298631579 57895894737 122224666667 366674000001 1100022000003