110002200120213 has 8 divisors (see below), whose sum is σ = 146914457592000. Its totient is φ = 73212371364288.

The previous prime is 110002200120119. The next prime is 110002200120223. The reversal of 110002200120213 is 312021002200011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 110002200120213 - 2⁹ = 110002200119701 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110002200120192 and 110002200120201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110002200120223) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30607176868 + ... + 30607180461.

It is an arithmetic number, because the mean of its divisors is an integer number (18364307199000).

Almost surely, 2^{110002200120213} is an apocalyptic number.

It is an amenable number.

110002200120213 is a deficient number, since it is larger than the sum of its proper divisors (36912257471787).

110002200120213 is an equidigital number, since it uses as much as digits as its factorization.

110002200120213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61214357931.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 110002200120213 its reverse (312021002200011), we get a palindrome (422023202320224).

The spelling of 110002200120213 in words is "one hundred ten trillion, two billion, two hundred million, one hundred twenty thousand, two hundred thirteen".