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11000231103103 = 111000021009373
BaseRepresentation
bin1010000000010011000011…
…0111100000101001111111
31102221121112000111221011121
42200010300313200221333
52420211433130244403
635221234132531411
72213511660422314
oct240046067405177
942847460457147
1011000231103103
113561198756110
121297b03180b67
1361a41827b458
142a05b2132d0b
1514121bb093bd
hexa0130de0a7f

11000231103103 has 4 divisors (see below), whose sum is σ = 12000252112488. Its totient is φ = 10000210093720.

The previous prime is 11000231103089. The next prime is 11000231103109. The reversal of 11000231103103 is 30130113200011.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-11000231103103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000231103109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500010504676 + ... + 500010504697.

It is an arithmetic number, because the mean of its divisors is an integer number (3000063028122).

Almost surely, 211000231103103 is an apocalyptic number.

11000231103103 is a deficient number, since it is larger than the sum of its proper divisors (1000021009385).

11000231103103 is a wasteful number, since it uses less digits than its factorization.

11000231103103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1000021009384.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11000231103103 its reverse (30130113200011), we get a palindrome (41130344303114).

The spelling of 11000231103103 in words is "eleven trillion, two hundred thirty-one million, one hundred three thousand, one hundred three".

Divisors: 1 11 1000021009373 11000231103103