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11000233303103 = 111000021209373
BaseRepresentation
bin1010000000010011000011…
…1111111001110000111111
31102221121112011122201000002
42200010300333321300333
52420211434211144403
635221234252024515
72213512015214312
oct240046077716077
942847464581002
1011000233303103
113561199a18aa0
121297b03a6213b
1361a41886b925
142a05b2546979
1514121bde1188
hexa0130ff9c3f

11000233303103 has 4 divisors (see below), whose sum is σ = 12000254512488. Its totient is φ = 10000212093720.

The previous prime is 11000233303099. The next prime is 11000233303109. The reversal of 11000233303103 is 30130333200011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11000233303103 - 22 = 11000233303099 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000233303109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500010604676 + ... + 500010604697.

It is an arithmetic number, because the mean of its divisors is an integer number (3000063628122).

Almost surely, 211000233303103 is an apocalyptic number.

11000233303103 is a deficient number, since it is larger than the sum of its proper divisors (1000021209385).

11000233303103 is a wasteful number, since it uses less digits than its factorization.

11000233303103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1000021209384.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 11000233303103 its reverse (30130333200011), we get a palindrome (41130566503114).

The spelling of 11000233303103 in words is "eleven trillion, two hundred thirty-three million, three hundred three thousand, one hundred three".

Divisors: 1 11 1000021209373 11000233303103