11000241400133 has 4 divisors (see below), whose sum is σ = 11139484962240. Its totient is φ = 10860997838028.

The previous prime is 11000241400103. The next prime is 11000241400147. The reversal of 11000241400133 is 33100414200011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11000241400133 is a prime.

It is a super-2 number, since 2×11000241400133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000241400103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69621780935 + ... + 69621781092.

It is an arithmetic number, because the mean of its divisors is an integer number (2784871240560).

Almost surely, 2^{11000241400133} is an apocalyptic number.

It is an amenable number.

11000241400133 is a deficient number, since it is larger than the sum of its proper divisors (139243562107).

11000241400133 is an equidigital number, since it uses as much as digits as its factorization.

11000241400133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 139243562106.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 11000241400133 its reverse (33100414200011), we get a palindrome (44100655600144).

The spelling of 11000241400133 in words is "eleven trillion, two hundred forty-one million, four hundred thousand, one hundred thirty-three".