Base | Representation |
---|---|
bin | 10100011111010101… |
… | …10100011100000001 |
3 | 1001101122000012120011 |
4 | 22033222310130001 |
5 | 140012034120223 |
6 | 5015314344521 |
7 | 536412006211 |
oct | 121752643401 |
9 | 31348005504 |
10 | 11000301313 |
11 | 4735424211 |
12 | 216bb8b141 |
13 | 1064001841 |
14 | 764d4c241 |
15 | 445aed80d |
hex | 28fab4701 |
11000301313 has 4 divisors (see below), whose sum is σ = 11579264560. Its totient is φ = 10421338068.
The previous prime is 11000301311. The next prime is 11000301329. The reversal of 11000301313 is 31310300011.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11000301313 - 21 = 11000301311 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11000301293 and 11000301302.
It is not an unprimeable number, because it can be changed into a prime (11000301311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289481595 + ... + 289481632.
It is an arithmetic number, because the mean of its divisors is an integer number (2894816140).
Almost surely, 211000301313 is an apocalyptic number.
It is an amenable number.
11000301313 is a deficient number, since it is larger than the sum of its proper divisors (578963247).
11000301313 is an equidigital number, since it uses as much as digits as its factorization.
11000301313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 578963246.
The product of its (nonzero) digits is 27, while the sum is 13.
Adding to 11000301313 its reverse (31310300011), we get a palindrome (42310601324).
The spelling of 11000301313 in words is "eleven billion, three hundred one thousand, three hundred thirteen".
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