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1100030143 = 2115213413
BaseRepresentation
bin100000110010001…
…0010000010111111
32211122220022200011
41001210102002333
54223101431033
6301053244051
736155046652
oct10144220277
92748808604
101100030143
11514a35a23
12268493627
13146b91614
14a6149899
156688eccd
hex419120bf

1100030143 has 4 divisors (see below), whose sum is σ = 1105243768. Its totient is φ = 1094816520.

The previous prime is 1100030089. The next prime is 1100030147. The reversal of 1100030143 is 3410300011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100030143 - 217 = 1099899071 is a prime.

It is a Duffinian number.

It is a zygodrome in base 3.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100030147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2606496 + ... + 2606917.

It is an arithmetic number, because the mean of its divisors is an integer number (276310942).

Almost surely, 21100030143 is an apocalyptic number.

1100030143 is a deficient number, since it is larger than the sum of its proper divisors (5213625).

1100030143 is an equidigital number, since it uses as much as digits as its factorization.

1100030143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5213624.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1100030143 is about 33166.7023232639. The cubic root of 1100030143 is about 1032.2895444671.

Adding to 1100030143 its reverse (3410300011), we get a palindrome (4510330154).

The spelling of 1100030143 in words is "one billion, one hundred million, thirty thousand, one hundred forty-three".

Divisors: 1 211 5213413 1100030143