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11000312300002 = 25500156150001
BaseRepresentation
bin1010000000010011010110…
…1101010000000111100010
31102221121201200022011101011
42200010311231100013202
52420212114422100002
635221250153131134
72213513664532054
oct240046555200742
942847650264334
1011000312300002
11356122a574593
121297b263b9aaa
1361a42c03a55c
142a05bcc2b8d4
15141223ce78d7
hexa0135b501e2

11000312300002 has 4 divisors (see below), whose sum is σ = 16500468450006. Its totient is φ = 5500156150000.

The previous prime is 11000312299993. The next prime is 11000312300009. The reversal of 11000312300002 is 20000321300011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10925794765561 + 74517534441 = 3305419^2 + 272979^2 .

It is not an unprimeable number, because it can be changed into a prime (11000312300009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750078074999 + ... + 2750078075002.

Almost surely, 211000312300002 is an apocalyptic number.

11000312300002 is a deficient number, since it is larger than the sum of its proper divisors (5500156150004).

11000312300002 is an equidigital number, since it uses as much as digits as its factorization.

11000312300002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5500156150003.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 11000312300002 its reverse (20000321300011), we get a palindrome (31000633600013).

Subtracting 11000312300002 from its reverse (20000321300011), we obtain a palindrome (9000009000009).

The spelling of 11000312300002 in words is "eleven trillion, three hundred twelve million, three hundred thousand, two".

Divisors: 1 2 5500156150001 11000312300002