Base | Representation |
---|---|
bin | 1010000000010011011000… |
… | …1011110100001011001101 |
3 | 1102221121202020101012210022 |
4 | 2200010312023310023031 |
5 | 2420212123444441023 |
6 | 35221251040551525 |
7 | 2213514122611514 |
oct | 240046613641315 |
9 | 42847666335708 |
10 | 11000320312013 |
11 | 356123404708a |
12 | 1297b290225a5 |
13 | 61a4308b42a6 |
14 | 2a05bdd1567b |
15 | 14122487b7c8 |
hex | a01362f42cd |
11000320312013 has 8 divisors (see below), whose sum is σ = 11375055833856. Its totient is φ = 10626827695200.
The previous prime is 11000320311991. The next prime is 11000320312057. The reversal of 11000320312013 is 31021302300011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11000320312013 - 210 = 11000320310989 is a prime.
It is a super-2 number, since 2×110003203120132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11000320311982 and 11000320312000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11000320312063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 310708256 + ... + 310743657.
It is an arithmetic number, because the mean of its divisors is an integer number (1421881979232).
Almost surely, 211000320312013 is an apocalyptic number.
It is an amenable number.
11000320312013 is a deficient number, since it is larger than the sum of its proper divisors (374735521843).
11000320312013 is an equidigital number, since it uses as much as digits as its factorization.
11000320312013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 621452515.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11000320312013 its reverse (31021302300011), we get a palindrome (42021622612024).
The spelling of 11000320312013 in words is "eleven trillion, three hundred twenty million, three hundred twelve thousand, thirteen".
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