110004012420013 has 8 divisors (see below), whose sum is σ = 110292149495808. Its totient is φ = 109715880138384.

The previous prime is 110004012419869. The next prime is 110004012420037. The reversal of 110004012420013 is 310024210400011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110004012420013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110004012423013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47320920 + ... + 49591102.

It is an arithmetic number, because the mean of its divisors is an integer number (13786518686976).

Almost surely, 2^{110004012420013} is an apocalyptic number.

It is an amenable number.

110004012420013 is a deficient number, since it is larger than the sum of its proper divisors (288137075795).

110004012420013 is a wasteful number, since it uses less digits than its factorization.

110004012420013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2397083.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 110004012420013 its reverse (310024210400011), we get a palindrome (420028222820024).

The spelling of 110004012420013 in words is "one hundred ten trillion, four billion, twelve million, four hundred twenty thousand, thirteen".