Base | Representation |
---|---|
bin | 10100011111010110… |
… | …10100111010001001 |
3 | 1001101122020222000002 |
4 | 22033223110322021 |
5 | 140012102344223 |
6 | 5015321252345 |
7 | 536413102031 |
oct | 121753247211 |
9 | 31348228002 |
10 | 11000434313 |
11 | 4735505130 |
12 | 21700340b5 |
13 | 106404a23b |
14 | 764d848c1 |
15 | 445b27e28 |
hex | 28fad4e89 |
11000434313 has 32 divisors (see below), whose sum is σ = 12846092160. Its totient is φ = 9314403840.
The previous prime is 11000434303. The next prime is 11000434321. The reversal of 11000434313 is 31343400011.
It is a cyclic number.
It is not a de Polignac number, because 11000434313 - 24 = 11000434297 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11000434303) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5689895 + ... + 5691827.
It is an arithmetic number, because the mean of its divisors is an integer number (401440380).
Almost surely, 211000434313 is an apocalyptic number.
It is an amenable number.
11000434313 is a deficient number, since it is larger than the sum of its proper divisors (1845657847).
11000434313 is a wasteful number, since it uses less digits than its factorization.
11000434313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2409.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 11000434313 its reverse (31343400011), we get a palindrome (42343834324).
The spelling of 11000434313 in words is "eleven billion, four hundred thirty-four thousand, three hundred thirteen".
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