Base | Representation |
---|---|
bin | 10100011111010110… |
… | …11010000010111001 |
3 | 1001101122022000212100 |
4 | 22033223122002321 |
5 | 140012104032403 |
6 | 5015321534013 |
7 | 536413220256 |
oct | 121753320271 |
9 | 31348260770 |
10 | 11000455353 |
11 | 4735519a18 |
12 | 2170044309 |
13 | 10640569a4 |
14 | 764d8c42d |
15 | 445b2e2a3 |
hex | 28fada0b9 |
11000455353 has 24 divisors (see below), whose sum is σ = 16835844168. Its totient is φ = 6897480192.
The previous prime is 11000455351. The next prime is 11000455379. The reversal of 11000455353 is 35355400011.
11000455353 is a `hidden beast` number, since 1 + 100 + 0 + 4 + 553 + 5 + 3 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 8554955049 + 2445500304 = 92493^2 + 49452^2 .
It is not a de Polignac number, because 11000455353 - 21 = 11000455351 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11000455351) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 204351 + ... + 252507.
It is an arithmetic number, because the mean of its divisors is an integer number (701493507).
Almost surely, 211000455353 is an apocalyptic number.
It is an amenable number.
11000455353 is a deficient number, since it is larger than the sum of its proper divisors (5835388815).
11000455353 is a wasteful number, since it uses less digits than its factorization.
11000455353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49673 (or 49670 counting only the distinct ones).
The product of its (nonzero) digits is 4500, while the sum is 27.
Adding to 11000455353 its reverse (35355400011), we get a palindrome (46355855364).
The spelling of 11000455353 in words is "eleven billion, four hundred fifty-five thousand, three hundred fifty-three".
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