Base | Representation |
---|---|
bin | 10100011111011010… |
… | …11111000001110011 |
3 | 1001101200022201001100 |
4 | 22033231133001303 |
5 | 140012224000201 |
6 | 5015341335443 |
7 | 536420646306 |
oct | 121755370163 |
9 | 31350281040 |
10 | 11001000051 |
11 | 4735861188 |
12 | 2170267583 |
13 | 10641b78b2 |
14 | 765090b3d |
15 | 445bda886 |
hex | 28fb5f073 |
11001000051 has 24 divisors (see below), whose sum is σ = 15985681920. Its totient is φ = 7290082800.
The previous prime is 11001000047. The next prime is 11001000053. The reversal of 11001000051 is 15000010011.
It is not a de Polignac number, because 11001000051 - 22 = 11001000047 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a junction number, because it is equal to n+sod(n) for n = 11000999997 and 11001000042.
It is not an unprimeable number, because it can be changed into a prime (11001000053) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1726810 + ... + 1733168.
It is an arithmetic number, because the mean of its divisors is an integer number (666070080).
Almost surely, 211001000051 is an apocalyptic number.
11001000051 is a deficient number, since it is larger than the sum of its proper divisors (4984681869).
11001000051 is a wasteful number, since it uses less digits than its factorization.
11001000051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7487 (or 7484 counting only the distinct ones).
The product of its (nonzero) digits is 5, while the sum is 9.
Adding to 11001000051 its reverse (15000010011), we get a palindrome (26001010062).
The spelling of 11001000051 in words is "eleven billion, one million, fifty-one", and thus it is an aban number and an uban number.
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