1100100100018 has 4 divisors (see below), whose sum is σ = 1650150150030. Its totient is φ = 550050050008.

The previous prime is 1100100099991. The next prime is 1100100100019. The reversal of 1100100100018 is 8100010010011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 646089617209 + 454010482809 = 803797^2 + 673803^2 .

It is a super-2 number, since 2×1100100100018² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100100099980 and 1100100100007.

It is not an unprimeable number, because it can be changed into a prime (1100100100019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275025025003 + ... + 275025025006.

Almost surely, 2^{1100100100018} is an apocalyptic number.

1100100100018 is a deficient number, since it is larger than the sum of its proper divisors (550050050012).

1100100100018 is an equidigital number, since it uses as much as digits as its factorization.

1100100100018 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 550050050011.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 1100100100018 its reverse (8100010010011), we get a palindrome (9200110110029).

The spelling of 1100100100018 in words is "one trillion, one hundred billion, one hundred million, one hundred thousand, eighteen".