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1100101100103 = 361509055007
BaseRepresentation
bin10000000000100011001…
…000101010001001000111
310220011112221022012000000
4100000203020222021013
5121011001340200403
62201213544252343
7142323350031015
oct20004310521107
93804487265000
101100101100103
11394606433aa5
121592597710b3
137c97ba15715
143b360aa38b5
151d9397c17a3
hex1002322a247

1100101100103 has 14 divisors (see below), whose sum is σ = 1649397123744. Its totient is φ = 733400732916.

The previous prime is 1100101100093. The next prime is 1100101100107. The reversal of 1100101100103 is 3010011010011.

It is not a de Polignac number, because 1100101100103 - 25 = 1100101100071 is a prime.

It is a super-2 number, since 2×11001011001032 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100101100107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 13 ways as a sum of consecutive naturals, for example, 754526775 + ... + 754528232.

Almost surely, 21100101100103 is an apocalyptic number.

1100101100103 is a deficient number, since it is larger than the sum of its proper divisors (549296023641).

1100101100103 is an frugal number, since it uses more digits than its factorization.

1100101100103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1509055025 (or 1509055010 counting only the distinct ones).

The product of its (nonzero) digits is 3, while the sum is 9.

Adding to 1100101100103 its reverse (3010011010011), we get a palindrome (4110112110114).

The spelling of 1100101100103 in words is "one trillion, one hundred billion, one hundred one million, one hundred thousand, one hundred three".

Divisors: 1 3 9 27 81 243 729 1509055007 4527165021 13581495063 40744485189 122233455567 366700366701 1100101100103